What is the Acceleration with a Coefficient of Kinetic Friction of 0.2?

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SUMMARY

The discussion centers on calculating the acceleration of a system involving a 1.0 kg hanging mass and a 4.0 kg block on a table, with a coefficient of kinetic friction (\muk) of 0.2. The acceleration can be determined using Newton's second law and the frictional force acting on the block. The frictional force is calculated as the product of the coefficient of kinetic friction and the normal force, which is equal to the weight of the block. The final acceleration is derived from the net force acting on the system.

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\muk

i don't know what it means??
 
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Context helps.
 
Pengwuino said:
Context helps.


1. Suppose a hanging 1.0kg lab mass is attached to a 4.0kg block on the table


a. If the coefficient of kinetic friction, \muk is .2, what is the acceleration?
 
jtwitty said:
\muk

i don't know what it means??

At a guess I'd say the coefficient of kinetic friction, but it is difficult to tell without any context and Pengwuino said.
 
jtwitty said:
1. Suppose a hanging 1.0kg lab mass is attached to a 4.0kg block on the table


a. If the coefficient of kinetic friction, \muk is .2, what is the acceleration?
Here
 

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