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## Homework Statement

A uniform ladder 5.1 m long rests against a frictionless, vertical wall with its lower end 3.1 m from the wall. The ladder weighs 165 N. The coefficient of static friction between the foot of the ladder and the ground is 0.39 . A painter weighing 739 N climbs slowly up the ladder.

What is the actual size of the frictional force when the painter has climbed 0.9393 m along the ladder?

## Homework Equations

## The Attempt at a Solution

I am so confused on this type of torque problem. I do not even know where to begin.

this is what i came up with.

I used where the ladder touches the floor as my pivot point.

t = torque

t

_{man}+ t

_{ladder}- t

_{fric}= 0

165N(0.9393m) + 739N(5.1/2m) - f

_{s}(5.1) = 0

i feel like i am leaving some stuff out :(

I am greatly confused and any help would be very appreciated.

Thank you :)

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