A uniform ladder 5.1 m long rests against a frictionless, vertical wall with its lower end 3.1 m from the wall. The ladder weighs 165 N. The coefficient of static friction between the foot of the ladder and the ground is 0.39 . A painter weighing 739 N climbs slowly up the ladder.
What is the actual size of the frictional force when the painter has climbed 0.9393 m along the ladder?
The Attempt at a Solution
I am so confused on this type of torque problem. I do not even know where to begin.
this is what i came up with.
I used where the ladder touches the floor as my pivot point.
t = torque
tman + tladder - tfric = 0
165N(0.9393m) + 739N(5.1/2m) - fs(5.1) = 0
i feel like i am leaving some stuff out :(
I am greatly confused and any help would be very appreciated.
Thank you :)