What is the amount of work done in moving the box from the bottom to t

[TheLetterDex]

Homework Statement

A 160 Newton box sits on a 10 meter long frictionless plane inclined at an angle of 30° to the horizontal as shown. Force (F) applied to a rope attached to the box causes the box to move with a constant speed up the incline.

Calculate the amount of work done in moving the box from the bottom to the top of the inclined plane.
_____ J

The Attempt at a Solution

So far i come up with h=u*t-0.5*g*t^2, but now sure where to go

 

[Nathanael]

So far i come up with h=u*t-0.5*g*t^2, but now sure where to go

What is "h" and what is "u"?


There is a simple way to do this based on conservation of energy. None of the energy is lost to friction.

 

[TheLetterDex]

What is "h" and what is "u"?


There is a simple way to do this based on conservation of energy. None of the energy is lost to friction.

Yeah I am not sure where i was going with this very confused with the question

 

[Nathanael]

Yeah I am not sure where i was going with this very confused with the question

The problem says to find the work done.

Work is (or "causes") a change in energy.

Does the box change it's energy at all from the bottom of the incline to the top?

 

[HalfLostAndSearching]

from thereI would like to clarify that the work done in physics is defined as the product of the force applied and the distance over which the force is applied. In this scenario, the force applied is the component of the weight of the box (mg) along the incline, which is given by F=mg*sin(30°). The distance over which this force is applied is the height of the incline, which is given by h=10*sin(30°). Therefore, the work done in moving the box from the bottom to the top of the inclined plane can be calculated as W=F*h=mg*sin(30°)*10*sin(30°)=80 J. This is the amount of work done in moving the box against gravity and does not take into account any work done by the force applied to maintain a constant speed.