What is the angle θ between the tow rope and the center line

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SUMMARY

The discussion centers on calculating the angle θ between the tow rope and the center line of a ski boat, given a boat speed of 15 m/s, a rope tension of 90 N, and 3700 N of work done over a distance of 54.8 m. The key equation used is work = force x Δdistance, leading to a calculated work of 4932 J from the tension. However, since only 3700 N of work is performed, the angle θ is crucial to determine the effective force contributing to the work done.

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  • Familiarity with trigonometric functions, specifically cosine
  • Ability to interpret free body diagrams
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Angela_vaal
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Homework Statement


Water skiers often ride to one side of the center line of a boat, as shown in the figure (Figure 1) . In this case, the ski boat is traveling at 15 m/s and the tension in the rope is 90 N.If the boat does 3700 N of work on the skier in 54.8 m, what is the angle θ between the tow rope and the center line of the boat?
Walker4e.ch07.Pr017.jpg


Homework Equations


work=force x Δdistance

The Attempt at a Solution


I feel all over the place with this one. I don't know where to start. All i know is that I will be getting the angle of cosine since movement is in the horizontal direction.
 
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Angela_vaal said:
work=force x Δdistance
So you have a force of 90 N, and you have a distance of 54.8 meters. What if you multiply those two together? You get 4932 J. That number is larger than the 3700 N (Newton? units are wrong on the 3700) of work stated in the problem. So apparently, all of that 90 N force is not being used to perform work. So the angle θ has to somehow come into play. How much of that 90 N force is being used to produce work?
 
just to add on what TomHart said... free body diagrams are very helpful...
 

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