What is the Angular Velocity of a Disk and Rod Combination?

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SUMMARY

The discussion focuses on calculating the angular velocity of a combination of a uniform disk and a nonrotating rod after they interact. The disk rotates at 9.5 revolutions per second (rev/s) and has a moment of inertia represented by the equation I1 = 1/2mr^2. The rod, which has the same mass as the disk and a length equal to the disk's diameter, contributes to the total moment of inertia with I2 = 1/12ml^2. The conservation of angular momentum principle is applied to find the combined angular velocity (ω2) after the rod is dropped onto the disk.

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Bones
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Homework Statement


A uniform disk turns at 9.5 rev/s around a frictionless spindle. A nonrotating rod, of the same mass as the disk and length equal to the disk's diameter, is dropped onto the freely spinning disk, see the figure. They then turn together around the spindle with their centers superposed. What is the angular velocity of the combination?




Homework Equations





The Attempt at a Solution



I1w1= 1/2mr^2*9.5rev/sec
I2w2= 1/12ml^2*w2
That's as far as I got...is it even right??
 
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Bones said:
A uniform disk turns at 9.5 rev/s around a frictionless spindle. A nonrotating rod, of the same mass as the disk and length equal to the disk's diameter, is dropped onto the freely spinning disk, see the figure. They then turn together around the spindle with their centers superposed. What is the angular velocity of the combination?

I1w1= 1/2mr^2*9.5rev/sec
I2w2= 1/12ml^2*w2
That's as far as I got...is it even right??

Hi Bones! :smile:

(have an omega: ω :wink:)

Sort-of … the Is are right …

but you need conservation of angular momentum,

so for the "after" side, you'll need the total I, = I1 + I2, so that you can find (I1 + I22. :smile:
 

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