What is the Apparent Weight on a Ferris Wheel?

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SUMMARY

The apparent weight of a rider on a Ferris wheel varies based on their position. At the top of the Ferris wheel, the normal force (Fn) is calculated using the equation Fn - mg + Fc = 0, while at the bottom, it is Fn - mg - Fc = 0. Given a Ferris wheel with a radius of 7.2 meters, completing one revolution every 28 seconds, and a rider mass of 55kg, the calculations reveal distinct apparent weights at both positions due to the effects of centripetal force (Fc) and gravitational force (mg).

PREREQUISITES
  • Understanding of circular motion equations
  • Knowledge of gravitational force calculations
  • Familiarity with centripetal force concepts
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate the centripetal acceleration for the Ferris wheel using the formula a = v²/r
  • Determine the velocity of the Ferris wheel using the circumference and period of rotation
  • Explore the relationship between normal force and apparent weight in circular motion
  • Investigate real-world applications of centripetal force in amusement park rides
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for practical examples of force dynamics in real-world scenarios.

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Homework Statement



As you ride on a ferris wheel, your apparent weight is different at the top and bottom. Calculate your apparent weight at the top and bottom of a Ferris wheel, given that the radius of the wheel is 7.2 meters, it completes one revolution every 28 seconds, and your mass is 55kg.

Homework Equations



Any circular motion equations

The Attempt at a Solution



I don't even know where to start
 
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When the circle is below you, Fn - mg - Fc = 0. Where Fn is normal force and Fc is centripetal force.
Fn - mg + Fc = 0 when the circle is above you.
 

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