How Do You Calculate the Force on a Ferris Wheel Rider at a Specific Point?

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SUMMARY

The discussion focuses on calculating the total force acting on a Ferris wheel rider, specifically a 42 kg individual, when positioned one quarter revolution past the highest point on a Ferris wheel with a radius of 25 m. The Ferris wheel completes one revolution every 20 seconds, establishing a constant rotational speed. Key calculations involve understanding circular motion and centripetal acceleration to determine both the magnitude and direction of the force at the specified position.

PREREQUISITES
  • Circular motion principles
  • Centripetal acceleration calculations
  • Understanding of force vectors
  • Basic trigonometry for diagramming
NEXT STEPS
  • Calculate centripetal force using the formula F = m * v² / r
  • Learn about gravitational force and its impact on circular motion
  • Explore the relationship between period and speed in circular motion
  • Graph force as a function of Ferris wheel period
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Physics students, amusement park engineers, and anyone interested in the dynamics of circular motion and force calculations in real-world scenarios.

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Just before finals you decide to visit an amusement park set up in the Metrodome. Since it is a weekend, you invite your favorite niece along. She loves to ride on a Ferris wheel, and there is one at the amusement park. The Ferris wheel has seats on the rim of a circle with a radius of 25 m. The Ferris wheel rotates at a constant speed and makes one complete revolution every 20 seconds. While you wait, your niece who has a mass of 42 kg, rides the Ferris wheel. [B]To kill time you decide to calculate the total force (both magnitude and direction) on her when she is one quarter revolution past the highest point. [/B]Because the Ferris wheel can be run at different speeds, you also decide to make a graph which gives the magnitude of the force on her at that point as a function of the period of the Ferris wheel.

please help me..Of course I know circular motion,centripetal acceleration etc..but I can't understand this bold part.
 
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The bold part just specifies the location of the person at the moment of interest. You need that to specify the direction of the force on her. (Draw yourself a diagram.)
 

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