Why Subtract Non-Cleaning Area in Windshield Wiper Sector Calculations?

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Homework Help Overview

The problem involves calculating the area cleaned by a windshield wiper blade, which is part of a larger arm that rotates through a specified angle. The original poster is confused about why the area not cleaned by the blade is subtracted from the total area of the sector formed by the wiper's motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the reasoning behind subtracting the area not cleaned by the blade from the total area of the sector. They question whether simply calculating the area cleaned by the blade would suffice.
  • Some participants discuss the differences in calculations based on the radius used, questioning the correctness of various approaches.
  • Others suggest considering the implications of the wiper's length and the position of the cleaning blade in relation to the pivot point.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been provided regarding the need to consider the entire area and the implications of the wiper's design, but no consensus has been reached on the best approach to take.

Contextual Notes

Participants note that the cleaning part of the wiper is located at the end of the arm, which may affect the calculations. There is also mention of the angle of rotation and its conversion to radians, which is relevant to the area calculations.

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Homework Statement


The total arm and blade of a single windshield wiper was 10 in. long and rotated back and forth through an angle of 95°. A portion of the windshield is cleaned by 7-in. wiper blade. What is the area of the region cleaned?


Homework Equations


Area of a sector = 1/2 r2θ


The Attempt at a Solution


My first guess was to simply calculate the area cleaned by the blade and I thought that would be my answer.

In the book though, they calculated the area not cleaned by the blade (r would be equal to (10-7)2) and subtracted it from the total area. I can't wrap my head around that. Why subtract the two areas? Why not just calculate the area that was cleaned by the blade? My guess is it has something to do with the actual angle or radius, but I'd like a little clarification to make sure I really understand this. Thanks!
 

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hi theintarnets! :smile:

there is a difference between θ/2 * (102 - 72) and θ/2 * (10 - 7)2

which one is correct?
 
They were using the portion not cleaned by the blade which was equal to 3 in., so (10-7) was used for r, and then squared.
 
Last edited:
so they used θ/2 * (102 - 32) ?

what do you think is wrong with that?

what do you think it should be?
 
theintarnets said:

The Attempt at a Solution


My first guess was to simply calculate the area cleaned by the blade and I thought that would be my answer.
OK, well, that's what the question asks for. Show us how you would do that.

Imagine a worn-out wiper arm, total length 10", that only has 1" of cleaning blade at the end. How would that calculation look different?
 
What I had done was just use 7 for r, thinking that since the cleaning blade was 7 inches, the area cleaned would be 1/2*(7)^2*whatever 95 degrees in radians is. But they way you put it does make me think about it a little more. I guess the area cleaned by blade 1 inch long is much more different than the area cleaned by the last inch of a 10 inch blade. So then the only way to figure it out would be to get the whole area, then subtract the area that the blade isn't cleaning. Am I right?
 
yup! :biggrin:
 
Did you draw a picture? One thing you need to know, that you did not state, is that the 7" 'cleaning' part of the wiper is at the end of the 10" wiper. IF the 'cleaning' part had started at the pivot point, then you would only need the 7" part. Of course, anyone who has looked at a windshield wiper knows the 'cleaning' part is at the end opposite the wiper.
 

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