What is the average velocity for a bicycle's trip?

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tag16
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Homework Statement


A bicycle travels 3.2 km due east in 0.10 h, then 4.7 km at 15.0° east of north in 0.14 h, and finally another 3.2 km due east in 0.10 h to reach its destination. The time lost in turning is negligible. What is the average velocity for the entire trip?
I need to find the magnitude and direction in degrees


Homework Equations



average velocity= rf-ri/t1-t2 but there is 3 different times and distances not two...

The Attempt at a Solution



I tried to do vector addition A+B and B+C then add them together but that didn't work to well.
 
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tag16 said:

Homework Statement


A bicycle travels 3.2 km due east in 0.10 h, then 4.7 km at 15.0° east of north in 0.14 h, and finally another 3.2 km due east in 0.10 h to reach its destination. The time lost in turning is negligible. What is the average velocity for the entire trip?
I need to find the magnitude and direction in degrees

Homework Equations



average velocity= rf-ri/t1-t2 but there is 3 different times and distances not two...

The Attempt at a Solution



I tried to do vector addition A+B and B+C then add them together but that didn't work to well.

You need to resolve the vectors into their x,y components, then determine the total displacement. That will yield your direction.

For average V = |D|/Total time.

Where |D| is the magnitude of your Displacement determined above, where

D = A + B + C
 
I found the initial velocity for x and y by using the formulas 4.7cos(15.0)= 4.539
4.7sin(15.0)= 1.216
delta t=0.10+0.14
Then I found the x and y components by doing: delta rx= vix(delta t)+0= 1.089
delta ry= viy (delta t)-1/2g(delta t)^2=-1.136
Then I added A+B+C for x and y: x=3.2+1.089+3.2=7.48
y=0+.0096+0
Then added them and took the square root. Then divided that number by the total time. Didn't workout to well...
 
Ok. Try this way.

A = 3.2 i + 0 j

B = 4.7*Sin15 i + 4.7*Cos15 j

C = 3.2 i + 0 j

Then add them together

D = (6.4 + 4.7*sin15) i + 4.7cos 15 j

Your Δt is (.1 + .14 + .1)

Your answer will be in km/h