What is the axis of symmetry of quadratic function f(x)=-2x^2-(1/2)

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SUMMARY

The axis of symmetry for the quadratic function f(x) = -2x^2 - (1/2) is determined using the formula x = -b/(2a). In this case, the coefficients are a = -2 and b = 0, leading to the calculation x = -0/(2 * -2) = 0. Therefore, the statement that the axis of symmetry is x = -2 is false. The correct axis of symmetry is x = 0.

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Lucas7105
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The problem is:
f(x)=-2x^2-(1/2)
Determine if this statement is true of false:
The axis of symmetry is x=-2.
What is the axis of symmetry? How can you figure out the axis of symmetry without a b value, since the formula for it is x=-b/2a
 
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Hello, and welcome to MHB! (Wave)

What if you write the given function in the equivalent form:

$$f(x)=-2x^2+0x-\frac{1}{2}$$
 
Can someone tell me how to even remember all this? I watch at this and don't understand.
 

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