MHB What is the axis of symmetry of quadratic function f(x)=-2x^2-(1/2)

AI Thread Summary
The axis of symmetry for the quadratic function f(x) = -2x^2 - (1/2) is determined using the formula x = -b/(2a). In this case, the function can be rewritten as f(x) = -2x^2 + 0x - (1/2), where a = -2 and b = 0. Substituting these values into the formula yields x = 0, indicating that the axis of symmetry is x = 0, not x = -2. Understanding this concept can be challenging, but focusing on the coefficients in the standard form of the quadratic equation can help. The correct axis of symmetry for the given function is x = 0.
Lucas7105
Messages
1
Reaction score
0
The problem is:
f(x)=-2x^2-(1/2)
Determine if this statement is true of false:
The axis of symmetry is x=-2.
What is the axis of symmetry? How can you figure out the axis of symmetry without a b value, since the formula for it is x=-b/2a
 
Mathematics news on Phys.org
Hello, and welcome to MHB! (Wave)

What if you write the given function in the equivalent form:

$$f(x)=-2x^2+0x-\frac{1}{2}$$
 
Can someone tell me how to even remember all this? I watch at this and don't understand.
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Back
Top