MHB What is the axis of symmetry of quadratic function f(x)=-2x^2-(1/2)

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The axis of symmetry for the quadratic function f(x) = -2x^2 - (1/2) is determined using the formula x = -b/(2a). In this case, the function can be rewritten as f(x) = -2x^2 + 0x - (1/2), where a = -2 and b = 0. Substituting these values into the formula yields x = 0, indicating that the axis of symmetry is x = 0, not x = -2. Understanding this concept can be challenging, but focusing on the coefficients in the standard form of the quadratic equation can help. The correct axis of symmetry for the given function is x = 0.
Lucas7105
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The problem is:
f(x)=-2x^2-(1/2)
Determine if this statement is true of false:
The axis of symmetry is x=-2.
What is the axis of symmetry? How can you figure out the axis of symmetry without a b value, since the formula for it is x=-b/2a
 
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Hello, and welcome to MHB! (Wave)

What if you write the given function in the equivalent form:

$$f(x)=-2x^2+0x-\frac{1}{2}$$
 
Can someone tell me how to even remember all this? I watch at this and don't understand.
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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