MHB What is the axis of symmetry of quadratic function f(x)=-2x^2-(1/2)

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The axis of symmetry for the quadratic function f(x) = -2x^2 - (1/2) is determined using the formula x = -b/(2a). In this case, the function can be rewritten as f(x) = -2x^2 + 0x - (1/2), where a = -2 and b = 0. Substituting these values into the formula yields x = 0, indicating that the axis of symmetry is x = 0, not x = -2. Understanding this concept can be challenging, but focusing on the coefficients in the standard form of the quadratic equation can help. The correct axis of symmetry for the given function is x = 0.
Lucas7105
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The problem is:
f(x)=-2x^2-(1/2)
Determine if this statement is true of false:
The axis of symmetry is x=-2.
What is the axis of symmetry? How can you figure out the axis of symmetry without a b value, since the formula for it is x=-b/2a
 
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Hello, and welcome to MHB! (Wave)

What if you write the given function in the equivalent form:

$$f(x)=-2x^2+0x-\frac{1}{2}$$
 
Can someone tell me how to even remember all this? I watch at this and don't understand.
 
Thread 'Erroneously finding discrepancy in transpose rule'

Thread 'Erroneously finding discrepancy in transpose rule'

Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...
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