What is the Bessel-Parseval relation and how does it work?

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    Bessel Relation
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The Bessel-Parseval relation connects the integral of the square of a function in the time domain to the integral of the square of its Fourier transform in the frequency domain. Specifically, for a complex function f, the theorem states that the integral of the absolute square of f over all space equals the integral of the absolute square of its Fourier transform. This relationship simplifies understanding in the discrete case, where it aligns with the Pythagorean theorem. The Bessel-Parseval theorem is considered highly useful in various applications of Fourier analysis. Its implications extend to both continuous and discrete functions, enhancing its significance in mathematical physics.
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Domnu said:
The following link: http://electron6.phys.utk.edu/QM1/modules/m1/free_particle.htm mentions something about the Bessel-Parseval relation... could someone explain what this is exactly and how it works?

If you have an L2(R) (complex) function f whose Fourier transform writes
\tilde{f}(q) = \int_{-\infty}^{+ \infty} dq f(x) e^{-2 \pi i qx }
then the Bessel-Parseval theorem states that
\int_{-\infty}^{+\infty} \left| f(x) \right|^2 dx = \int_{-\infty}^{+\infty} \left| \tilde{f}(q) \right|^2 dq

This theorem also works (and is simpler to understand) in the discret case i.e. considering the Fourier series of f as a specific case of the general Pythagore theorem.
 
Wowww... are you serious? The theorem must be ridiculously helpful then...
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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