What is the Bessel-Parseval relation and how does it work?

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    Bessel Relation
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SUMMARY

The Bessel-Parseval relation establishes a fundamental connection between a function and its Fourier transform. Specifically, for an L2(R) complex function f, the relation is expressed as ∫_{-∞}^{+∞} |f(x)|² dx = ∫_{-∞}^{+∞} |ŧf(q)|² dq, where ŧf(q) is the Fourier transform of f. This theorem simplifies understanding in discrete cases, aligning with the general Pythagorean theorem. Its implications are significant for analyzing the energy distribution of functions in both continuous and discrete domains.

PREREQUISITES
  • Understanding of L2(R) space and complex functions
  • Familiarity with Fourier transforms and their properties
  • Basic knowledge of the Pythagorean theorem in mathematical contexts
  • Conceptual grasp of energy distribution in functions
NEXT STEPS
  • Study the properties of Fourier transforms in detail
  • Explore applications of the Bessel-Parseval relation in signal processing
  • Learn about the implications of the Pythagorean theorem in functional analysis
  • Investigate the differences between continuous and discrete Fourier transforms
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Mathematicians, physicists, and engineers involved in signal processing, as well as students studying Fourier analysis and functional analysis.

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Domnu said:
The following link: http://electron6.phys.utk.edu/QM1/modules/m1/free_particle.htm mentions something about the Bessel-Parseval relation... could someone explain what this is exactly and how it works?

If you have an L2(R) (complex) function [tex]f[/tex] whose Fourier transform writes
[tex]\tilde{f}(q) = \int_{-\infty}^{+ \infty} dq f(x) e^{-2 \pi i qx }[/tex]
then the Bessel-Parseval theorem states that
[tex]\int_{-\infty}^{+\infty} \left| f(x) \right|^2 dx = \int_{-\infty}^{+\infty} \left| \tilde{f}(q) \right|^2 dq[/tex]

This theorem also works (and is simpler to understand) in the discret case i.e. considering the Fourier series of [tex]f[/tex] as a specific case of the general Pythagore theorem.
 
Wowww... are you serious? The theorem must be ridiculously helpful then...
 

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