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What is the bicycle speed after the throw?

  1. Nov 25, 2007 #1
    1. The problem statement, all variables and given/known data

    Tony of mass 55kg coasts on his bi cycle of mass 5 kg at a constant speed of 5m/s carrying a 6kg pack. tony throws his pack forward, in the direction of his motion, at 1 m/s relative to the speed of bicycle just before the throw.

    Initial momentum of system (tony, bicycle, pack) is 330 kg* m/s
    Momentum of system after pack is thrown is 330 kg*m/s

    What is the bicycle speed after the throw? Answer in kg*m/s

    2. Relevant equations



    3. The attempt at a solution

    330 / 5 = 66 kg*m/s

    or 330 / 61 = 5.41 kg*m/s
     
    Last edited by a moderator: Mar 7, 2013
  2. jcsd
  3. Nov 25, 2007 #2

    rl.bhat

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    Homework Helper

    Momentum of system after pack is thrown is 330 kg*m/s = (Mass of tony + Cycle)*v + Mass of the pack*its velocity. Velocity of pack with respect to the ground is 5 + 1 = 6m/s.
     
  4. Nov 26, 2007 #3
    Thanks i got the answer!
     
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