What is the bicycle speed after the throw?

[sensesfail]

Homework Statement

Tony of mass 55kg coasts on his bi cycle of mass 5 kg at a constant speed of 5m/s carrying a 6kg pack. tony throws his pack forward, in the direction of his motion, at 1 m/s relative to the speed of bicycle just before the throw.

Initial momentum of system (tony, bicycle, pack) is 330 kg* m/s
Momentum of system after pack is thrown is 330 kg*m/s

What is the bicycle speed after the throw? Answer in kg*m/s

Homework Equations

The Attempt at a Solution

330 / 5 = 66 kg*m/s

or 330 / 61 = 5.41 kg*m/s

 

[rl.bhat]

Momentum of system after pack is thrown is 330 kg*m/s = (Mass of tony + Cycle)*v + Mass of the pack*its velocity. Velocity of pack with respect to the ground is 5 + 1 = 6m/s.

 

[sensesfail]

Thanks i got the answer!