Bicycle Forces in Circular Motion

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SUMMARY

The discussion centers on calculating forces acting on a bicycle in circular motion, specifically for a bicyclist traveling at a constant speed of 8.62 m/s in a circle with a radius of 22.5 m. The mass of the bicycle-rider combination is 79 kg. The force of friction on the bicycle from the road is calculated to be 260.9 N using the formula F = mv²/R. The net force on the bicycle requires consideration of both the applied force from the rider and the frictional force, which acts in the opposite direction.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with circular motion dynamics
  • Knowledge of force calculations using F = mv²/R
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of centripetal force in circular motion
  • Learn how to calculate net force in multi-directional scenarios
  • Explore the role of friction in motion dynamics
  • Investigate the effects of varying mass and speed on circular motion forces
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Physics students, educators, and anyone interested in understanding the mechanics of circular motion and force calculations in real-world applications, such as cycling dynamics.

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Homework Statement



A bicyclist travels in a circle of radius 22.5 m at a constant speed of 8.62 m/s. The bicycle-rider mass is 79 kg. Calculate the magnitudes of (a) the force of friction on the bicycle from the road and (b) the net force on the bicycle from the road.

Homework Equations


a. F=mv^2/R
Fnet=ma

The Attempt at a Solution


i got a. to be 260.9N by using F=mv^2/R
for b, i have no idea. Could they be the same since the vertical forces on the bike cancel out?
 
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to answer b, you need to find the force applied by the biker (f=ma) then to get fnet you need to add the force applied + the force of friction. but keep in mind that the force of friction would be negative since it is going the opposite direction :)
 

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