What is the Brewster Angle for Circularly Polarized Light?

[Mary 006]

Homework Statement

Hello everybody. I have a big problem with this important problem that i can't solve and i have no solution ... A circularly polarized monochromatic wave is reflected from a dielectric mirror which has parameters μ and ε. Its wave vector is k = (k0, 2k0,0). Find the magnetic field B, the electric field E and the Poynting vector S as well as the angle of incidence for which the reflected wave is linearly polarized (i.e. the Brewster angle). Calculate the energy of the system.

Homework Equations

The Attempt at a Solution

I think we have to use this (very) general equations :
B = B0.sin(ωt + δ)
rot E = - ∂B/∂t
E = -ωB0.cos (ωt + δ)
where : ω=k.c = 2∏c/λ
For the circular polarization, the electric field rotates about its axis in a circle.
Then, for linear polarization: E remains in the same plane.
For the Poynting vector : S = B x E / μ (i am not sure if for this equation i have to use μ or μo (in vacuum)). Then we can calculate the energy, I guess ...
About the angle Brewster, i think we have to use the Fresnel equations (but i don't know how ...).
I wonder whether it would be better to use the equations in the complex form (instead of the actual form equations (real form)).

Can you help me, please ? Thank you in advance.
I know that what i have written is not very usefull ... And I'm sorry.

 

[Simon Bridge]

Thing about how reflection works for different polarizations, and how you can resolve circular polarization into components wrt the plane of the mirror.