Interference of circularly polarized waves

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SUMMARY

The discussion centers on calculating the intensity of two left circularly polarized monochromatic plane waves, S2 and S3, arriving at the xy plane with a specific incidence angle θ. The user derives the electromagnetic vector at the xy plane by summing the polarization vectors for both waves, represented as $$\vec e_1$$ and $$\vec e_2$$. The intensity formula used is $$ I = \frac{εc} {n} \langle \vec E_r^2 \rangle $$, which incorporates the contributions from both waves. The user seeks confirmation on whether the intensity calculation holds true for circularly polarized waves, given the dephasing of TE and TM components.

PREREQUISITES
  • Understanding of circularly polarized light and its mathematical representation.
  • Familiarity with electromagnetic wave equations and intensity calculations.
  • Knowledge of polarization states, specifically TE and TM modes.
  • Basic principles of wave interference and vector addition in physics.
NEXT STEPS
  • Explore the mathematical representation of circularly polarized waves in detail.
  • Research the effects of polarization on wave interference patterns.
  • Learn about the relationship between intensity and polarization states in electromagnetic waves.
  • Investigate the implications of wave propagation at angles other than parallel to the z-axis.
USEFUL FOR

Students and professionals in physics, particularly those studying optics and electromagnetic theory, as well as researchers working with wave polarization and interference phenomena.

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Homework Statement


Two (left) circularly polarized monochromatic plane waves S2 and S3 arrive at the xy plane with an incidence angle θ (see figure). Find the intensity of the light projected in the xy plane.
a2dl74_th.png

(Nevermind S1, it is only mentioned in another part of the problem)

Homework Equations

The Attempt at a Solution


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I've written down the expression for a monochromatic plane wave circularly polarized using $$\vec e_1 = sinθ\vec i + cos θ \vec j $$ $$\vec e_2 = \vec j$$ as the basis for the polarization vector for S2 and $$\vec e_1 = -sinθ\vec i + cosθ \vec j $$ $$\vec e_2 = \vec j$$ for S3. Then the electromagnetic vector at the xy plane its just the sum of them both.

Now the intensity would be $$ I = \frac{εc} {n} \langle \vec E_r^2 \rangle = \frac{εc} {c} \vec E · \vec E^* = \frac{εc} {c} (\vec E_1 + \vec E_2)·(\vec E_1^* + \vec E_2 ^*)$$, but to get to this point every source I've found has assumed that both waves are linearly polarized, so I'm not sure if it would be the same with other polarizations. I don't see why not, but I would like to confirm it before going on.
 
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First of all for circular polarization, the TE and TM components of the light are dephased by 900, which doesn't seem to manifest in your expression for the unit vectors. Second, since the incoming beams are not parallel to the z axis, therefore you must expect that the E field has a component along the z-direction.
 

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