What is the buoyant force acting on the rock?

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SUMMARY

The buoyant force acting on a submerged rock with a volume of 0.2 m³ in water with a density of 1000 kg/m³ is calculated using the formula F_b = ρgV. Substituting the values, the buoyant force is determined to be 1960 N. The calculation confirms that the buoyant force is directly proportional to the volume submerged and the density of the fluid, emphasizing the importance of using the correct expression for buoyant force.

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mike2007
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A rock with a volume of 0.2m3 is fully sumberged in water with density of 1000kg/m3. What is the buoyant force acting on the rock?

Assume that gravity acts on the system
0.2m3*9.81m/s2 = 1.96
buoyant force = 1000kg/m3*1.96
= 1960N
?
 
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Check the units of your answer. You do not have the correct expression for buoyant force. The buoyant force on an object also depends upon the volume submerged:

F_b=\rho g V where V is the volume submerged.
 
Ok, i get it now. makes it a lot clearer.
thanks
 

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