What is the Capacitance of a Capacitor When a Conductor is Inserted?

Click For Summary
SUMMARY

The capacitance of an isolated capacitor with an initial capacitance of C = 1 µF and charge Q = 22 µC increases when a conductor is inserted. The conductor, which is 1/3 the thickness of the capacitor, effectively reduces the distance between the plates, leading to an increase in capacitance. The correct approach involves recognizing that the insertion of the conductor creates two capacitors in series, each with a capacitance of 3 µF. The combined capacitance of these two capacitors in series is calculated using the formula for capacitors in series, resulting in a total capacitance of 1.5 µF.

PREREQUISITES
  • Understanding of capacitor fundamentals and capacitance calculations
  • Familiarity with the concept of capacitors in series and parallel
  • Knowledge of the formula for capacitance: C = Q / V
  • Basic principles of electric fields and potential difference
NEXT STEPS
  • Study the effects of dielectric materials on capacitance
  • Learn about the formula for capacitors in series and parallel configurations
  • Explore the relationship between electric field strength and capacitance
  • Investigate practical applications of capacitors in electronic circuits
USEFUL FOR

This discussion is beneficial for electrical engineering students, physics learners, and anyone interested in understanding capacitor behavior in circuits, particularly in the context of modifying capacitance through physical changes in configuration.

electricblue7
Messages
4
Reaction score
0

Homework Statement




An isolated capacitor with capacitance C = 1 µF has a charge Q = 22 µC on its plates.
Now a conductor is inserted into the capacitor. The thickness of the conductor is 1/3 the thickness of the capacitor and is centered in between the plates of the capacitor.

What is the capacitance of the capacitor with the conductor in place?

Homework Equations



Q = C / V

V = E d


The Attempt at a Solution



I know that since the capacitor is a conductor it makes the distance between the two plates smaller which means that the capacitance should therefore increase. I thought that since we now had two distances that were each 1/3 the original distance the capacitance would increase by a factor of 6 however this answer does not work. Can anyone help me please?!?
 
Physics news on Phys.org
After introduction of conductor, each capacitor is three times the original capacitor. Now these two capacitors are in series. Then what will be the combined capacitor?
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
1K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K