What is the Centripetal Acceleration of a Car on a Circular Curve?

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SUMMARY

The centripetal acceleration of a car negotiating a flat circular curve with a radius of 50 meters and a speed of 20 m/s is calculated using the formula Ac = V2/R. Substituting the values, Ac equals 8 m/s2. The maximum centripetal force provided by static friction is 1.2 × 104 N, which confirms that the car can maintain this acceleration without losing traction.

PREREQUISITES
  • Understanding of centripetal acceleration
  • Familiarity with the formula Ac = V2/R
  • Basic knowledge of forces, specifically static friction
  • Ability to perform basic algebraic calculations
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  • Study the effects of varying radius on centripetal acceleration
  • Learn about the role of static friction in maintaining circular motion
  • Explore real-world applications of centripetal acceleration in vehicle dynamics
  • Investigate the relationship between speed and required centripetal force
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Students studying physics, automotive engineers, and anyone interested in the dynamics of vehicles on curved paths.

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Homework Statement



A car is negotiating a flat circular curve of radius 50 m with a speed of 20 m/s. The maximum centripetal force (provided by static friction) is 1.2 × 104 N. What is the centripetal acceleration of the car?


Homework Equations



MAc = MV^2/R

The Attempt at a Solution



20^2 / 50 = 8 m/s^2 ?
 
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robvba said:

Homework Statement



A car is negotiating a flat circular curve of radius 50 m with a speed of 20 m/s. The maximum centripetal force (provided by static friction) is 1.2 × 104 N. What is the centripetal acceleration of the car?


Homework Equations



MAc = MV^2/R

The Attempt at a Solution



20^2 / 50 = 8 m/s^2 ?

Not sure, but I think you're right. I have no idea what the second sentence actually means, but it might just be a red herring. Cent acc is just velocity squared over radius, and they gave you that in the first sentence.
 

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