What is the Centripetal Acceleration of a Race Car on a Circular Track?

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SUMMARY

The centripetal acceleration of a race car traveling around a circular track with a diameter of 1.00 km at a constant speed of 90.0 km/h is calculated using the formula Ac = v²/r. The radius of the track is determined to be 0.50 km (or 500 meters), which is half of the diameter. Substituting the values into the equation, the centripetal acceleration is found to be 16.2 m/s². This calculation is essential for understanding the forces acting on the car during circular motion.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula (Ac = v²/r)
  • Knowledge of converting units (km/h to m/s)
  • Basic geometry to calculate the radius from the diameter
  • Familiarity with the concept of circular motion in physics
NEXT STEPS
  • Learn how to convert speed from km/h to m/s for physics calculations
  • Explore the effects of varying speed on centripetal acceleration
  • Study the relationship between radius and centripetal acceleration in different scenarios
  • Investigate real-world applications of centripetal acceleration in motorsports
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as anyone interested in the dynamics of race cars on circular tracks.

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Homework Statement



I am having difficulty with a problem: A race care goes around a level, circular track with a diameter of 1.00 km at a constant speed of 90.0 km/h. Wha tis the car<s centripetal acceleration in m/s^2?

Homework Equations



Ac=v^2/r

The Attempt at a Solution



I'm not quite sure if I'm supposed to find the radius of the 1.00 diameter or if I simply use the 1.00 km as my radius in the above equation...?
 
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..[tex]a=\frac{v^2}{r}[/tex]

r=radius...so yes you must find the radius(which is half of the diameter!).
 
Radius is half the diameter.
 

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