What is the centripetal acceleration of the hammer in circular motion?

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SUMMARY

The centripetal acceleration of a hammer in circular motion, when whirled by an athlete, is calculated to be 51 m/s². This value is derived using the formula for centripetal acceleration, ac = 4π²r/T², where r is the radius (1.3 m) and T is the period of revolution (1.0 s). The confusion arose from misapplying the formula, as the correct approach involves ensuring the period is squared in the denominator. The correct calculation confirms the result of 51 m/s².

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Homework Statement



An athlete whirls a 7.00 kg hammer tied to the end of a 1.3 m chain in horizontal chain. The hammer makes one complete revolution in 1.0 s.
(A) What is the centripetal acceleration of the hammer? 51 m/s2



Homework Equations


ac=4pi^2*r/r^2


The Attempt at a Solution


I know the formula for centripetal acceleration is as above. but how is the answer 51?
I put it in my calculator and did not get that...
4(3.14^2)(1.3)/1.3^2)

What am i doing wrong??
 
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