What is the centroid of a C-shape?

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Homework Help Overview

The discussion revolves around finding the centroid of a C-shaped object, with dimensions provided in millimeters. Participants are exploring the calculation of centroids using area-weighted averages for both x and y coordinates.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss dividing the shape into rectangular parts to facilitate centroid calculations. There are varying assumptions about the origin's placement and the resulting coordinates for the centroid. Some participants express confusion about whether the centroid can lie outside the physical shape.

Discussion Status

The conversation is ongoing, with participants providing different methods for calculating the centroid and questioning the implications of their results. There is no explicit consensus on the correct coordinates, and some participants are exploring the concept of centroids in relation to shapes that may not have their centroids on their surfaces.

Contextual Notes

Participants are working under the assumption that the centroid calculations must consider the areas of the divided shapes, and there is a mention of potential confusion regarding the geometric properties of centroids in relation to the shapes being analyzed.

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Homework Statement



http://prntscr.com/fcbm8

Find the centroid - All dimensions are in mm

Homework Equations



xbar = (A1X1+A2X2) / (A1+A2)

Similarly for Ybar I assume

The Attempt at a Solution



I got the y co-ordinate to be 20.428mm, and would assume that the x coordinate would be 5mm.

Is this right?
 
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You can divide the shape into three rectangular parts several different ways but I used two vertical lines in the obvious places. I assumed the origin is in the bottom left corner.

xbar = (A1X1+A2X2+A3X3) / (A1+A2+A3)

= (700*5 + 800*30 +400*30) / (700+800+400)
= 20.789

ybar = (A1Y1+A2Y2+A3Y3) / (A1+A2+A3)

= (700*35 + 800*10 + 400*65) / (700+800+400)
= 30.789

Best show your working as my answer is quite different.
 
This is what confused me, does this mean the centroid is not on the shape itself?
 
In this case yes. Where would the centroid of a doughnut be?
 
CWatters said:
In this case yes. Where would the centroid of a doughnut be?
In the center, of course. That's what the "centroid" is- the geometric center. If you were to represent the doughnut as two circled in the in the xy-plane, centered at the origin with radii r and R, and then have other circles as the thickness of the doughnut, the centroid would be at (0, 0, 0).
 
I know. I was using it as an obvious example for the OP to think about. eg a shape that has a centroid that's not on the surface of the shape.
 
Yeah, I was probably thinking more about a centroid of a mass, but even then, there's still the donut which proves me redundant.
 

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