What Is the Change in Entropy for Condensing and Freezing 45g of H2O?

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SUMMARY

The change in entropy for condensing and freezing 45g of H2O is calculated through three distinct phases: condensation of water vapor at 100 degrees Celsius, cooling of liquid water to 0 degrees Celsius, and freezing of water to solid. The specific heat of liquid water is 4.2 J K-1g-1, with the heat of vaporization at 2258 J g-1 and the heat of fusion at 334 J g-1. The total change in entropy is determined to be -386.3 J/K after correctly applying the entropy formula dS = dq/T for each phase.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically entropy.
  • Familiarity with the specific heat capacity of water and phase change enthalpies.
  • Knowledge of the formula dS = dq/T for calculating entropy changes.
  • Basic skills in logarithmic functions for calculating entropy during phase transitions.
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  • Study the concept of entropy in thermodynamics, focusing on phase transitions.
  • Learn about the specific heat capacities and enthalpies of various substances.
  • Explore advanced thermodynamic equations and their applications in real-world scenarios.
  • Investigate the implications of negative entropy changes in physical processes.
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This discussion is beneficial for students studying thermodynamics, particularly those focusing on phase changes and entropy calculations, as well as educators looking for practical examples to illustrate these concepts.

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Homework Statement



45g of H2O(g) are condensed at 100 degrees C, and H2O(l) is cooled to 0 degrees C and then frozen to H2O solid. Find the Change in Entropy


H2O(l): 4.2 J K-1g-1
vaporization at 100 degrees C: 2258 J g-1;
fusion at 0 degrees C: 334 J g

Homework Equations


dS=dq/T

The Attempt at a Solution


q1=(45g)(2258J/g) = -101610J
q2=(45g)(4.2J/K/g)(100K) = -18900J
q3=(45g)(334J/g)= -15030J

Total q=-135540J / 273.15K
delta S = -496.2J/K

I'm not sure if I did that right, can anybody double check? Thank you
 
Last edited:
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I think I solved my mistake, I'm not supposed to divide by T at the end, I need to do it for each step.

So q1= -101610J/373.15K = -272.3J/K
q2= 45gx4.2J/K/g x ln(273.15K/373.15K) = -58.96J/K
q3= -15030J/273.15K = -55.02J/K

Total Change in Entropy= -386.3J/K
 

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