What is the change in momentum for a baseball striking a fence at a 45° angle?

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SUMMARY

The change in momentum for a 138 g baseball striking a fence at a 45° angle can be calculated using vector notation. Initially, the baseball moves along the x-axis at 21.0 m/s, resulting in an initial momentum of 0.138 kg * 21.0 m/s = 2.898 kg·m/s in the i direction. After rebounding along the y-axis with the same speed, the final momentum is 0.138 kg * 21.0 m/s = 2.898 kg·m/s in the j direction. The change in momentum is thus represented as -2.898 i + 2.898 j kg·m/s.

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Homework Statement



A 138 g baseball, moving along the x-axis with speed 21.0 m/s, strikes a fence at a 45° angle and rebounds along the y-axis with unchanged speed. Give its change in momentum using unit vector notation.
_____ i + ______ j kg·m/s

Homework Equations



Momentum = (mass)(velocity)

The Attempt at a Solution



Honestly, our teacher hasn't taught us momentum, but gave us this assignment anyways. I'm really very confused. Any help would be great. :)
 
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Really all you need to use is conservation of momentum. The ball is going all in the x direction to start with, and then it is going all in the y direction. Figure out the difference between the components.
 
This has nothing to do with momentum- the problem is one of vectors, ie. a maths problem.

Draw or write the vector representing the initial and final momentae, then find the vector you need to add to the initial momentum vector to get the final momentum vector.
 

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