- #1
underduck
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1. A 0.095 kg tennis ball is traveling 40 m/s, hits a wall and travels in the opposite site direction it came from. The bounced leaving the wall with a speed of 30 m/s.
a. What is the change of momentum of the ball?
b. If the time contact is 20ms, find the impulse force.
m1= 0.095 v1= 40 m/s
m2= 0.095 v2= -30 m/s
My equation for:
a. change of momentum= (m1 x v1) - (m2 x v2)
(0.095 x 40) - (0.095 x -30) = 6.65 kg m/s
is this equation right?
b. i have no idea. i need some help here please :)
a. What is the change of momentum of the ball?
b. If the time contact is 20ms, find the impulse force.
m1= 0.095 v1= 40 m/s
m2= 0.095 v2= -30 m/s
My equation for:
a. change of momentum= (m1 x v1) - (m2 x v2)
(0.095 x 40) - (0.095 x -30) = 6.65 kg m/s
is this equation right?
b. i have no idea. i need some help here please :)