What is the closed form expression for f(a,b,n)?

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SUMMARY

The closed form expression for the function f(a,b,n) is derived from the partial differential equation (PDE) given by $$\frac{\partial }{\partial a}f(a,b,n)+\frac{\partial }{\partial b}f(a,b,n)=-n f(a,b,n+1)$$. The initial conditions are specified as $$f(a,b,0)=\frac{\pi }{2}$$ and $$f(a,b,1)=\frac{\pi }{2\sqrt{a b}}$$. The solution involves evaluating the definite integral $$\int_{0}^{\frac{\pi }{2}}\left ( a \, cos^2(x) +b \, sin^2(x) \right )^{-n}$$, which is independent of the variable c. This integral provides a method to compute f(a,b,n) for any integer n.

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hi, I do not know much about PDEs and programs like wolfram alpha and maple don't give me a solution.
it is possible to calculate the function through PDE?.
I would appreciate any help

$$\frac{\partial }{\partial a}f(a,b,n)+\frac{\partial }{\partial b}f(a,b,n)=-n f(a,b,n+1)$$

$$f(a,b,0)=\frac{\pi }{2} \: \; \, \,, \, \, \, f(a,b,1)=\frac{\pi }{2\sqrt{a b}}$$as we know ##f(a,b,1)## We can calculate ##f(a,b,2)\,,\,f(a,b,3),...##

But we could calculate closed form expression for ##f(a,b,n)## ?

thanks
 
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i reduce the problem to solve
$$\frac{\partial }{\partial c} \, g_{n}(c) = -n \, g_{n+1}(c)$$
with
$$g_{1}(c)=\frac{\pi }{2\sqrt{c^{2}+c}}$$
 
Do you need the result for all c?
 
Strum said:
Do you need the result for all c?
i found the solution, The function was the result of a definite integral.
thanks anyway :thumbup::thumbup:
 
Well if you found the solution I would like to see it. Please post it :)
 
the function is:
$$\int_{0}^{\frac{\pi }{2}}\left ( a \, cos^2(x) +b \, sin^2(x) \right )^{-n}$$
 
Ehh but this is not dependent on c as specified in post number 2.
 
evaluate the function as ##f(c,c+1,n)## and check
 

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