What is the coefficient of friction in this inclined plane problem?

Click For Summary
SUMMARY

The discussion focuses on calculating the coefficient of friction for a system involving two masses, m1 and m2, connected by a massless string over a pulley on a 30-degree incline. The given values include m2 = 5 kg, T = 10 N when stationary, and a distance of 0.5 m traveled in the first second, leading to an acceleration of 1 m/s². The calculated coefficient of friction is established as μ = 0.2, with the tension in the system when moving determined to be T = 11 N.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of forces acting on inclined planes
  • Familiarity with tension in strings and pulleys
  • Basic principles of friction and its coefficient
NEXT STEPS
  • Study the derivation of the coefficient of friction in inclined plane problems
  • Learn about the dynamics of systems involving pulleys and multiple masses
  • Explore advanced applications of Newton's laws in real-world scenarios
  • Investigate the effects of different angles of incline on friction and tension
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators seeking to clarify concepts related to tension and friction in dynamic systems.

nemo11
Messages
4
Reaction score
0

Homework Statement


Two bodies with mass m1 and m2 are tied together with an inexstensible and massless string rolled over a massless pulley put at the top of the incline with angle 30 . m2=5 kg which is on the incline is blocked and T=10 N . m2 is let loose and the system starts moving freely. The distance traveled in the first second is d=0.5 m . Calculate: coefficient of friction , T when the system is moving .
The answers given are : mu=0.2 and T=11 N. [/B]

Homework Equations



The Attempt at a Solution


So I find a=1 m/s
But what confuses me is the given T=10 N when the system is not moving.
m2gsinθ =5*10*0.5=25 N
So there is another force acting in the direction of T so that the system is not moving. Is that force the force of friction ?
Or how can I calculate the coefficient of friction?
I am confused.
What I get for mu is 0.34 .
 
Physics news on Phys.org
##T_i=10\,N## and ##a_i=0## when system not move.
When system rolling, ##a_1=a_2##
Now you can see the forces to ##m_2##.
 
I've solved it . Thank you !
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
8
Views
3K
Replies
14
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K