What Is the Coefficient of Kinetic Friction for a Box Pushed at Constant Speed?

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SUMMARY

The coefficient of kinetic friction for a box weighing 31 kg, pushed at a constant speed with a force of 85 N at an angle of -40 degrees, is determined by analyzing the forces acting on the box. The horizontal component of the applied force directly opposes friction, maintaining constant speed. Additionally, the applied force influences the normal force, which is essential for calculating the coefficient of kinetic friction using the formula μ_k = F_f / F_n, where F_f is the frictional force and F_n is the normal force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of force decomposition (horizontal and vertical components)
  • Familiarity with the concept of normal force
  • Basic grasp of friction coefficients and their calculations
NEXT STEPS
  • Study the decomposition of forces in inclined planes
  • Learn about calculating normal force in various scenarios
  • Explore the relationship between applied force and frictional force
  • Investigate real-world applications of kinetic friction in physics problems
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Physics students, educators, and anyone interested in understanding the principles of friction and force dynamics in mechanics.

Demonsthenes
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Okay, here's the question:

A box full of physics books (31 kg) is pushed across the floor at a constant speed by a force of F = 85 N at an angle theta = -40 degrees. Determine the coefficient of kinetic friction between the box and floor.

My question is (for later calculation) if the box is moving at constant speed, does the F = 85N really matter?
 
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Absolutely - that force (the horizontal component...) is what opposes the friction to keep the speed constant.
 
That force also affects the normal force, which you'll need to figure out to calculate the coefficient of kinetic friction.
 

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