What is the Colatitude Angle in Gravitation?

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Geostationary satellites maintain a fixed orbital radius and plane, crucial for their functionality. The discussion centers on determining the colatitude angle at which these satellites drop below the viewing horizon as one travels north or south. Participants seek clarification on the specific angle in question, referencing colatitude and related concepts. Visual aids are requested to enhance understanding of the angle involved. The conversation highlights the complexity of visualizing orbital mechanics in relation to Earth's curvature.
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Homework Statement


attachment.php?attachmentid=33789&stc=1&d=1136054222.jpg


The Attempt at a Solution



Please someone help me to understand the question
 

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Geostationary satellites have a specific orbital radius, and orbit in a particular plane. The Earth is spherical. As you travel northwards (or southwards), at what colatitude will the satellite drop below the viewing horizon?
 
attachment.php?attachmentid=33834&stc=1&d=1136082920.png

So which angle are we talking about?
 

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Hi gneill

can you mark the angle we are talking about in the image
its really getting hard for me to understand

is it this angle ? ...

attachment.php?attachmentid=33868&stc=1&d=1301667145.png


viz sin-1(.15)
 

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See attached.
 

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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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