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Demystifier said:Consider a physical system in which the average value of position is ##<x>=0##. What is the probability that the position is ##x=1## nm?
But if you also know \langle x^2 \rangle, \langle x^3 \rangle, ...?
Demystifier said:Consider a physical system in which the average value of position is ##<x>=0##. What is the probability that the position is ##x=1## nm?
Demystifier said:I think such a question can be meaningfully asked only by using mathematical equations.
Demystifier said:suppose that this trajectory can be explained theoretically by two different Hamiltonians
Demystifier said:Consider a physical system in which the average value of position is ##<x>=0##. What is the probability that the position is ##x=1## nm?
Yes.Blue Scallop said:Ok, mathematically.. if we remove the position basis.. then there would be no decoherence and no subsystems if there are no other basis to define it. And it's back to pure Hilbert space vectors with unit trace 1.
Yes.PeterDonis said:Is this possible?
Solution ##x(t)=0##.PeterDonis said:Can you give an actual example?