What Is The Complete Formula Of A Lever?

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SUMMARY

The complete formula for a lever must account for the weight of the lever itself, which acts at its center of mass. In the discussed scenario, the original formula F1D1 = F2D2 was modified to include the lever's weight, resulting in F1 x 2 feet > (F2 x 8 feet) + (3 feet x 100 lbs). This adjustment is crucial for accurately calculating the torque produced by the lever. The center of mass is located at the 5-foot mark for a uniform lever weighing 100 pounds.

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  • Understanding of basic physics principles, specifically torque and balance.
  • Familiarity with lever mechanics and the concept of center of mass.
  • Knowledge of how to apply formulas in practical scenarios.
  • Basic arithmetic skills for manipulating equations.
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  • Research the principles of torque in physics.
  • Learn about different types of levers and their applications.
  • Study the concept of center of mass in various objects.
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Students of physics, engineers, and anyone interested in understanding the mechanics of levers and their applications in real-world scenarios.

EnquiringMind
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In trying to solve a problem, I was using the simple F1D1 = F2D2 as the balance point of a lever. My limited physics knowledge knew no better.

My hypothetical involved using the "short side" of a lever to lift a weight on the long side of a lever.

After thinking about it... I realized I couldn't have a big cast iron lever and expect to balance it by placing 4 quarters on one end. I realized that the weight of the lever has to be factored in.

Since so many web pages talk about levers but never talk about this aspect, I am here hoping someone can tell me (or link me to) the COMPLETE formula of a lever.

Thank you for any help.

PS. I apologize if this is a redundant question, or if this is the wrong forum for this question. This place is so big that it's hard to find things.
 
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EnquiringMind said:
Since so many web pages talk about levers but never talk about this aspect, I am here hoping someone can tell me (or link me to) the COMPLETE formula of a lever.
To include the weight of the lever itself, just realize that its weight acts at its center of mass (for the purposes of calculating the torque it would produce).
 
My original formula, that did not include the weight of the lever, was...

F1 x 2 feet > F2 x 8 feet

As you can see, the lever is 10 feet long, and I want to lift the long side of the lever using the short side of the lever (hence, the ">" sign).

The center of mass of the entire lever would be at the 5 foot mark (3 feet to the right of the fulcrum). Let's say the entire lever is uniform and weighs 100 pounds.

Is my formula now F1 x 2 feet > (F2 x 8 feet) + (3 feet x 100 lbs)

Is that correct?
 
EnquiringMind said:
Is my formula now F1 x 2 feet > (F2 x 8 feet) + (3 feet x 100 lbs)

Is that correct?
Looks good to me.
 

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