What is the complex conjugate of this wave function?

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SUMMARY

The discussion centers on determining the normalization constant N for a wave function φ(x) that lacks complex components. Participants clarify that for a real wave function, the complex conjugate φ*(x) is equivalent to φ(x). The integral of φ*(x)φ(x) over the entire range must equal 1, confirming that φ*(x) is simply φ(x) when dealing with real values. The specific transformation mentioned, from x-x0 to x+x0, does not alter the fundamental nature of the wave function.

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gabriellelee
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Homework Statement
Find the value of N
Relevant Equations
x0 and delta are some constants
Screen Shot 2020-01-20 at 5.22.33 PM.png

I was planning to find the value of N by taking the integral of φ*(x)φ(x)dx from -∞ to ∞ = 1. However, this wave function doesn't have a complex number so I'm not sure what φ*(x) is. I was thinking φ*(x) is exactly the same φ(x), but with x+x0 instead of x-x0.

Thank you
 
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gabriellelee said:
Homework Statement:: Find the value of N
Homework Equations:: x0 and delta are some constants

View attachment 255845
I was planning to find the value of N by taking the integral of φ*(x)φ(x)dx from -∞ to ∞ = 1. However, this wave function doesn't have a complex number so I'm not sure what φ*(x) is. I was thinking φ*(x) is exactly the same φ(x), but with x+x0 instead of x-x0.

Thank you
Since it is real, its complex conjugate is just psi(x). x-x0 remains x-xo (assuming that they are real, which they surely are meant to be).
 
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