What Is the Concentration of Ions in Different Solutions?

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SUMMARY

The discussion focuses on calculating the concentration of ions in solutions, specifically using potassium iodide (KI) and barium hydroxide (Ba(OH)2) as examples. The concentration of iodide ions in a 1 mol dm-3 solution of KI is confirmed to be 1 M, as KI dissociates into K+ and I-. For the 0.01 mol dm-3 solution of Ba(OH)2, the concentration of hydroxide ions is determined to be 0.02 M due to the dissociation into Ba2+ and 2(OH)-. The key takeaway is understanding how to derive ion concentrations from the dissociation of compounds.

PREREQUISITES
  • Understanding of molarity and its calculation (mol dm-3)
  • Knowledge of ionic dissociation in solutions
  • Familiarity with chemical formulas and stoichiometry
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the dissociation of ionic compounds in aqueous solutions
  • Learn about molarity calculations and conversions
  • Explore stoichiometry in chemical reactions
  • Investigate the properties of strong vs. weak electrolytes
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Chemistry students, educators, and anyone seeking to understand ion concentration calculations in chemical solutions.

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Homework Statement


What is the concentration of ____ ions in a ___ mol dm-3 solution of ___?

Homework Equations


mass/molar mass = number of moles

volume/molar volume = number of moles

Not sure what other equations...

The Attempt at a Solution



I'm not understanding how this works. I have looked at the answers and I'm not really understanding it...

For example, the first question says:

"What is the concentration of iodide ions in a 1 mol dm-3 solution of KI?"

I really didn't know where to start, so I found that 1 mol dm-3 KI is the same as 166g dm-3 and didn't really know where to go from there. The answer sheet says the answer is 1. The next question asks the same thing, except for hydroxide ions in 0.01 mol dm-3 of Ba(OH)2, and the answer given is 0.02. It looks like they are multiplying the concentration by the number of ions. I'm not sure I understand why (I kind of keep getting glimpses of understanding which quickly fades).

Some help understanding why the answer is 1 would be appreciated (and why the answer for the second one is 0.02).

I know that KI dissociates into K+ and I-.

EDIT: Never mind, I think I understand now, I think it's because I was typing it I figured it out. Is it because;

KI -> K+ + I-

So concentration of K+ is 1M and I- is 1M.

And for the second, Ba(OH)2 -> Ba2+ + 2(OH)-

Since this is for 1M we have to divide all by 100, so ratio is 0.01:0.02 so 0.02 is the answer.

I think I understand now, correct me if wrong, thanks.
 
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Yes, you are correct. The molarity of a solute is defined as its concentration in mol dm-3.
 

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