What is the concentration of the HCl solution?

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SUMMARY

The concentration of the HCl solution is determined to be 0.105 mol/L. This conclusion is reached by neutralizing 10 mL of HCl with 10.5 mL of NaOH at a concentration of 0.100 mol/dm³. The calculation involves determining the moles of NaOH used, which is 1.05 x 10^-3 moles, and applying the stoichiometric relationship between HCl and NaOH to find the moles of HCl. Finally, the concentration is calculated by dividing the moles of HCl by the volume of the acid solution.

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I need to return an asignment today and i just can't figure it out (should be a piece of cake for the people that hangs around here)

There is 10ml HCl with an unknown concentration i a beaker. You let NaOH with the concentration 0,100 mol/dm3 drip into the acid until it is neutralized.
It takes 10,5ml NaOH to neutralize the acid.

With this you should be able to calculate the concentration of the acid or so my teacher say. And all i can do is sit here and look dumb while my brain refuses to cooperate

Could anyone help me i would owe you a life debt. If i don't get this in today i won't get a grade in chemistry
 
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I have posted hint at https://www.physicsforums.com/showthread.php?s=&postid=115160#post115160
 
10.5mL is 0.0105L

mols of NaOH:
0.0105L x 0.1mol/L = 1.05 x 10^-3 mols NaOH

mols of HCl:
1molHCl/1molNaOH * 1.05 x 10^-3 mols NaOH = 1.05 x 10^-3 mol HCl

concentration:
(1.05 x 10^-3 mol HCl) / 0.01L = 0.105 mol/L
 

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