What is the concept of fractal dimension and how is it computed?

  • Context: Undergrad 
  • Thread starter Thread starter hedipaldi
  • Start date Start date
  • Tags Tags
    Dimension Fractal
Click For Summary
SUMMARY

The discussion focuses on the concept of fractal dimension, specifically the Hausdorff dimension, and its computation using the Koch snowflake as an example. To calculate the fractal dimension, one must identify the number of new features added at each iteration and the scale of these features. For the Koch snowflake, the formula D = log(4)/log(3) yields a fractal dimension of approximately 1.2. Alternative methods, such as the box dimension, are also mentioned for approximating fractal dimensions in more complex shapes.

PREREQUISITES
  • Understanding of fractals and their properties
  • Familiarity with logarithmic functions
  • Basic knowledge of geometric constructions
  • Concept of iterative processes in mathematics
NEXT STEPS
  • Research the computation of the box dimension for complex shapes
  • Explore the mathematical properties of the Koch snowflake
  • Learn about other types of fractal dimensions, such as Minkowski and spectral dimensions
  • Investigate applications of fractal dimensions in real-world scenarios, such as in nature and computer graphics
USEFUL FOR

Mathematicians, educators, students in mathematics or physics, and anyone interested in the study of fractals and their applications.

hedipaldi
Messages
209
Reaction score
0
Hi,
Can someone give me a link to a clear and relatively basic and short matirial introducing the notion of fractal dimension (Hausdorff dimension)?
Thank's in advance.
 
Physics news on Phys.org
To compute a fractal dimension, you have to know how the object is "constructed". Let's use the Koch snowflake as an example:

362px-KochFlake.svg.png


To compute the fractal dimension, you have to know:

1) how many new features are added at every iteration
2) what scale the new feature has at every iteration

At the 0th iteration (top left), there's 3 lines each of the same length (let's call it L).

At the first iteration, we see that there are now 4 features per old but there are all 1/3 of the previous line.

At the second iteration, we add replace with 16 new features (4 for each of the last 4) and multiply the new Length, and each of those are 1/3 of the previous 1/3.

So we see a trend, for each iteration, n:

4^n new things added
(1/3)^n is the scaling factor

So we would say N = 4 and e = 1/3 and compute the fractional dimension:

D = log(N)/log(1/e) = log(4)/log(3) ~ 1.2

There are other ways to approximate a fractal dimension, like the box dimension. They are especially useful when you don't have a nice simple shape like the Koch snowflake.

Some external links:

3.3 Fractal Dimension

Fractal Dimension

Fractals & the Fractal Dimension
 
  • Like
Likes   Reactions: 1 person

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 26 ·
Replies
26
Views
5K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K