What is the Constant Volume Specific Heat for Diatomic Gases?

Click For Summary
SUMMARY

The constant volume specific heat (C_v) for diatomic gases is determined using the degrees of freedom (f) in thermodynamics. For diatomic gases, f is typically 5 at room temperature, increasing to 7 at higher temperatures due to the inclusion of vibrational modes. The relationship between specific heats is defined by the equation C_p - C_v = R, where C_p is the specific heat at constant pressure. The ratio of specific heats can be expressed as \(\frac{C_p}{C_v} = \lambda\), where \(\lambda = 1 + \frac{2}{f}\).

PREREQUISITES
  • Understanding of thermodynamic properties and tables
  • Familiarity with specific heat concepts (C_p and C_v)
  • Knowledge of degrees of freedom in gases
  • Basic grasp of gas laws and equations of state
NEXT STEPS
  • Research the derivation of the specific heat equations for different gas types
  • Explore the impact of temperature on degrees of freedom for diatomic gases
  • Study the implications of specific heat ratios in thermodynamic cycles
  • Investigate the behavior of gases under varying pressure and volume conditions
USEFUL FOR

Students and professionals in thermodynamics, chemical engineering, and physical chemistry, particularly those focusing on gas behavior and heat transfer in diatomic gases.

melanie
Messages
1
Reaction score
0
Just trying to locate specific heat constants with constant volume (not pressure), any ideas where to find this?
 
Physics news on Phys.org
If you have a thermodynamic set of property tables it would be in the column with Cv (v should be a subscript) if you are looking at Cp that is the specific heat at constant pressure. They should be fairly close in most non-extreme conditions so becareful what your looking at
 
C_p : Specific Heat at constant pressure
C_v : Specific Heat at constant volume

Also C_p - C_v = R

\frac {C_p}{C_v} = lamda

where lamda = 1 + \frac {2}{f}

Where f=degrees of freedon

for monoatomic gas , f=3
for diatomic gas , f=3

You can solve for two expressions at the top to get Cp

BJ
 
One correction to Dr.Brain's post. f for diatomic gases is 5
 
quark said:
One correction to Dr.Brain's post. f for diatomic gases is 5
And that's only at around room temperature's where the vibrational degree of freedom is absent. At high temperatures, f will be 7 for diatomic gases.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
836
  • · Replies 8 ·
Replies
8
Views
1K
Replies
16
Views
4K
Replies
5
Views
3K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K