What is the Convergence of the Infinite Sum with k^(1/k)?

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Homework Statement



Show that
[tex]\sum_{k=0}^{\infty} \sqrt[k]k-1[/tex]

converges.

Homework Equations



Ratio, radix theorems, comparison with other sums...


The Attempt at a Solution



No idea whatsoever.
Where does one begin in this case ? With other cases I'm quite confident.
 
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Hint:
Let the general term be denoted by:
[tex] a_k = \sqrt[k]{k} - 1[/tex]
Do you know how to prove that [itex]\lim_{k \rightarrow \infty}{a_k} = 0[/itex]?
Then, we have:
[tex] k = (1 + a_k)^{k}[/tex]
Taking the same equality for [itex]k + 1[/itex], and subtracting this one, you ought to get:
[tex] 1 = (1 + a_{k + 1})^{k + 1} - (1 + a_k)^{k}[/tex]
Solve this equation for [itex]a_{k + 1}[/itex]. What do you get?

Because as [itex]k \rightarrow \infty[/itex], [itex]a_k[/itex] is an infinitesimal quantity, you may expand your expression for [itex]a_{k + 1}[/itex] in powers of [itex]a_{k}[/itex] up to the first non-vanishing order. What do you get?

The solution for this asymptotic recursion relation would give you a comparison general term [itex]b_n[/itex], and the series [itex]\sum_{n = 1}^{\infty}{b_n}[/itex] is pretty easy to test for convergence. Then, you may use the [STRIKE]Ratio comparison test[/STRIKE].

EDIT:
Use the Asymptotic comparison test mentioned here instead.
 
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I don't quite follow you.

I sort of need simpler methods, thanks anyway.