What Is the Correct Inverse Laplace Transform of \( \frac{s+1}{s^2 - 4s + 4} \)?

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SUMMARY

The correct inverse Laplace transform of \( \frac{s+1}{s^2 - 4s + 4} \) is \( e^{2t} + 3te^{2t} \). This conclusion is derived using partial fraction decomposition, where \( \frac{s+1}{(s-2)^2} \) is expressed as \( \frac{1}{s-2} + \frac{3}{(s-2)^2} \). The initial miscalculation by the user involved incorrectly applying the partial fractions method, leading to an erroneous result of \( e^{2t} + 3e^{2t} \).

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cabellos
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inverse laplace question help please...

i am trying find the inverse laplace transfor of s+1/s^2 -4s +4

using partial fractions and solving my answer is e^2t + 3e^2t

however checking this in an online fourier-laplace calculator it comes up with e^2t + 3te^2t

who is correct? could you show me how you get your answer please...

thanks
 
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Hello cabellos,

I get the same result as your calculator. You might have made a mistake while using the partial fractions method.

\frac{s+1}{s^2-4s+4}=\frac{s+1}{(s-2)^2}=\frac{1}{s-2}+\frac{3}{(s-2)^2}

Regards,

nazzard
 
Last edited:
hi, oops I am not awake :zzz: ...i used s-2 as the denominator for both A and B. Thanks
:smile:
 

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