What Is the Correct Magnetic Field Strength at the Surface of a Wire?

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SUMMARY

The discussion focuses on calculating the magnetic field strength at the surface of a wire with a diameter of 1.0 mm carrying a current of 5.0 A. The correct formula used is B = (μ₀ * I) / (2 * π * r), where μ₀ is the permeability constant. The user initially calculated the magnetic field strength at a distance of 0.10 mm from the axis as 4 G, but incorrectly calculated the field strength at the surface, arriving at 0.001 T. The correct approach requires careful attention to units and the application of the formula.

PREREQUISITES
  • Understanding of magnetic field concepts
  • Familiarity with the permeability constant (μ₀)
  • Knowledge of current-carrying conductors
  • Basic algebra for manipulating equations
NEXT STEPS
  • Review the derivation of the magnetic field around a straight conductor
  • Learn about the applications of Ampère's Law in electromagnetism
  • Explore the significance of the permeability constant in different materials
  • Practice problems involving magnetic fields and current distributions
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding magnetic fields generated by current-carrying wires.

Lance WIlliam
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b]1. Homework Statement [/b]

What is the magnetic field strength 0.10 from the axis of a 1.0--diameter wire carrying 5.0 distributed uniformly over its cross section?
The answer is 4G I got the part right
Part B

What is the field strength at the surface of the wire?
I got this wrong...

Homework Equations




I got .001 I used the eqn (I can't find the symbol) but its the pereability consant...
so... (u_0_)(I)/2*pi*r

so...(4pi.e-7)(5)/2pi(.1e-3)



I got .001...
 
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Please provide the units in the statement of the problem.
 

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