What is the correct molar volume for a gas given its volume and moles?

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SUMMARY

The correct molar volume of a gas can be calculated by dividing the total volume by the number of moles. In this case, 3.0 moles of gas occupying 66 L results in a molar volume of 22 L. The commonly referenced value of 22.4 L pertains to ideal gases at standard temperature and pressure (STP), which may not apply to all gases under different conditions. Factors such as temperature, pressure, and the nature of the gas can affect the molar volume.

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Homework Statement



It's not an homework question. I'm trying to figure out this problem, but don't have any idea...

The question is, if 3.0 moles of gas has a volume of 66 L, then what is the molar volume of this gas?

I did like, 22.4 L * 1 atm / 273 K = 66 L * 1 atm / x, but what do I do with 3.0 moles?

What is wrong with my equation? Would you please help me out...?


Homework Equations





The Attempt at a Solution

 
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Whats the definition of molar volume?

I think you will find you are over complicating this :smile:

Molar volume is literally "volume per mole". If you have 3 moles and it occupies 66L, then the volume per mole is ... ?

That number you are using, 22.4, is the molar volume of an ideal gas at STP (spherical particles with no intermolecular interactions).
 
Last edited:
The molar volume is just the volume occupied by a mole of the substance in the gaseous state. So if 3 moles occupies 66 L the molar volume is just 22 L, simples!

Now you may be getting confused with already having known from somewhere that it is 22.4 L - the figure usually given. I don't know where the figures you gave came from but I can think of three possible reasons for the non-correspondence:

1 Where you got it from was content with a quite approximate figure - it's still right to within 2% after all;

2 22.4 L is at standard pressure (1 atm) and temperature (0°C or 25°C). Maybe this came from a volume under some other conditions;

3 It was a quite far from 'perfect' gas, maybe CO2 or something.
 

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