What is the correct power series for $g(t)$?

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SUMMARY

The correct power series for the function \( g(t) \) is the Taylor series, defined as \( g(t) = \sum_{n=0}^{\infty} \frac{(t-t_0)^n g^{(n)}(t_0)}{n!} \), where \( g^{(n)}(t_0) \) represents the \( n \)-th derivative of \( g \) evaluated at the point \( t_0 \). The initial recursive definition proposed in the discussion was incorrect, as it did not represent a valid function other than the zero function. The clarification provided emphasizes the importance of correctly identifying the derivatives in the Taylor series formulation.

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Dustinsfl
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What would be the power series of $g(t)$?

$$
g(t) = \sum_{n=0}^{\infty}\frac{g(t)}{n!}
$$

This?
 
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?? What EXACTLY are you trying to do? I'm guessing the recursive definition you have suggested is not a good way to go.
 
dwsmith said:
What would be the power series of $g(t)$?

$$
g(t) = \sum_{n=0}^{\infty}\frac{g(t)}{n!}
$$

This?

There is a mistake in your post, as posted there is no such function other than the zero function.

CB
 
The power series of a function around a point \( t_0 \) is $$ g(t) = \sum_{n=0}^{\infty} \frac{(t-t_0)^n g^{(n)}(t_0)}{n!} .$$ Note that the \( g^{(n)}(t_0) \) denotes the derivative evaluated at \( t_0 \), where \( g^{(0)}(t_0) = g(t_0) \).

Does this help you?

Edit: Sorry, to be specific this is the Taylor power series.
 
There was a mistake in what I was reading, i.e. is read it wrong. I see what my issue was so the question I asked was wrong.
 

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