What is the correct solution for the projectile question in yesterday's exam?

[Lord Dark]

Homework Statement

Hi everyone ,, yesterday I had an exam with the following question :
A ball is vertically thrown from a height (h) then it collide with the ground and went to height (5+h), the whole time of the projectile is 2 seconds .

(a) Find the initial velocity and the time it took until it reached the ground.
(b) Find (h) and the velocity before hitting the ground

Homework Equations

The Attempt at a Solution

The question was really hard ,, I didn't really know how to solve it .. I applied the following :
t1+t2=2 ,, and t1 (the time until it reached the ground) and t2(the time until it reached the height (h+5) , the equation of t1 (h=Vot1+0.5*g*t1^2) and for t2 (5-h=(V+gt1)t2-0.5*g*t2^2) and I combined them together and got V=7.5 m/s .. is it right ?? .. is the attempt to solve is even right ??

 

[LowlyPion]

Can't see the picture.

Is the ball thrown initially downward? That's what your equations reflect.

 

[LowlyPion]

... and for t2 (5-h=(V+gt1)t2-0.5*g*t2^2) and I combined them together and got V=7.5 m/s .. is it right ?? .. is the attempt to solve is even right ??

That doesn't look quite right.

Wouldn't it be more like

h + 5 = (V0 +g*T1)*T2 - 1/2*g*T2²

Is the 5 - h a typo ?

 

[Lord Dark]

it's true ,, it's h+5 ,, but can you tell me what is the answer you got ,, I just want to know if my answer is right or wrong

 

[LowlyPion]

it's true ,, it's h+5 ,, but can you tell me what is the answer you got ,, I just want to know if my answer is right or wrong

Sorry I didn't solve it. It looks a little tedious.

 

[Lord Dark]

it took me 1:30 hour in the exam and am still not sure if it's right or wrong -_-

 

[LowlyPion]

it took me 1:30 hour in the exam and am still not sure if it's right or wrong -_-

Well, you'll find out soon enough then. It's not like you can change it now.

Good luck.