- #1

annalian

- 56

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## Homework Statement

The particle thrown under the angle pi/6 rad. with the horizontal direction achieves the height h for t1=10S when going up and t2=50S when going down. Find initial speed v0 and height h.

## Homework Equations

h=v0y+gt^2/2

## The Attempt at a Solution

As h1=h2

v0y*t1-gt1^2/2=gt2^2/2

v*0.5*10-10*100/2=10*2500/2

v0=2600.

hmax:

v^2-vy0^2=2gh

vy0=v0*sin30=2600*0.5=1300

h=0-1300^2=2*(-10)*h

h=84500m.

Am i right?