What is the correlation of X and Z in terms of variance and covariance?

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SUMMARY

The discussion centers on calculating the covariance and correlation coefficient between independent random variables X and Z, where Z is defined as Z = X - Y. Given that Var(X) is 9 and Var(Y) is 7, the variance of Z is determined to be 16. The covariance Cov(X, Z) is derived using the property of independence, leading to the conclusion that Cov(X, Z) equals Cov(X, X - Y), which simplifies to Cov(X, X) - Cov(X, Y). The correlation coefficient ρXZ is calculated as Cov(X, Z) divided by the product of the square roots of Var(X) and Var(Z).

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CescGoal
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Very sorry that I've double posted but I realized i placed the original post in Precalculus.



1. Homework Statement
Question

Let X and Y be independent random variables with variances 9 and 7 respectively and let
Z = X - Y

a) What is the value of Cov(X,Z)
b) What is the value of the correlation coefficient of X and Z?

I've been stuck on this one question for 2-3 hours; its ridiculous, I know. Here's my terrible try.


3. The Attempt at a Solution
a)

Var(X) = 9
Var(Y) = 7

Var(X-Y) = Var(X) + Var(Y) = Var(Z)
Therefore, Var(Z) = 7 + 9 =16
Cov(X,Z) = E[XZ] - E[X]E[Z]


and b) \rhoXZ = \frac{Cov(X,Z)}{\sqrt{Var(X)*Var(Z)}}



= \frac{Cov(X,Z)}{\sqrt{9}*\sqrt{16}}
= \frac{Cov(X,Z)}{12}

Since last topic, I've realized that Cov(X,Y) = 0 due to independency. But I don't know how to use it.
 
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Cov(X,Z)=Cov(X,X-Y). Cov(X,X-Y)=Cov(X,X)-Cov(X,Y), right?
 


I didn't know about that law; thankyou very much.
 


CescGoal said:
I didn't know about that law; thankyou very much.

It's pretty obvious if you write out the definition of Cov. You should try and do that so you can see why it's true.
 

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