What is the current enclosed by a rectangular loop with given magnetic fields?

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Homework Help Overview

The problem involves applying Ampere's circuital law to determine the current enclosed by a rectangular loop situated in two regions with different magnetic field strengths. The magnetic fields are specified as 20 Am^-1 to the right and 30 Am^-1 to the left, with the loop dimensions given as 8 cm by 5 cm.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of Ampere's circuital law and the implications of the magnetic field values on the current enclosed. Questions arise regarding the configuration of the magnetic fields and the presence of the electric wire. Some participants express uncertainty about the contributions of different segments of the loop to the overall current.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the cancellation of contributions from opposing magnetic fields, and there is a recognition of the need to clarify the setup and assumptions involved.

Contextual Notes

There is a lack of clarity regarding the physical arrangement of the magnetic fields and the wire, as well as the movement of any components, which may affect the interpretation of the problem.

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Homework Statement



State Ampere's circuital law. The figure shows a region A in which the magnetic field [itex]H[/itex] and of value 20Am^-1 to the right and a region B in which the magnetic field [itex]H[/itex] is uniform and of value 30Am^-1 to the left. Find the current enclosed by the dashed rectangular loop, which has dimensions 8cm x 5cm.

Homework Equations



[itex]\int_c H\cdot dl[/itex][itex]= I_{enc}[/itex]


The Attempt at a Solution



So we already have a constant value for H for both segments and they are constant so I think its adding together two different values. So..

[itex]H \int \cdot dl = I_{enc} = H * (2x + y)[/itex] for x = 4cm and y = 5cm?

Or am I missing something?
 
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hi zhillyz! :smile:

(try using the X2 button just above the Reply box :wink:)
zhillyz said:
State Ampere's circuital law. The figure shows a region A in which the magnetic field [itex]H[/itex] and of value 20Am^-1 to the right and a region B in which the magnetic field [itex]H[/itex] is uniform and of value 30Am^-1 to the left. Find the current enclosed by the dashed rectangular loop, which has dimensions 8cm x 5cm.

i don't understand :redface:

where is the electric wire (for the current)?

what shapes are A and B, and where are they in relation to each other and the wire, and is anything moving? :confused:
 
Apologies perhaps the image itself will clarify and yes I have been that busy brushing up my Latex I forgot the more basic tools were there lol.

PastPaper.jpg
 
ah! :smile:
zhillyz said:
So we already have a constant value for H for both segments and they are constant so I think its adding together two different values. So..

[itex]H \int \cdot dl = I_{enc} = H * (2x + y)[/itex] for x = 4cm and y = 5cm?

Or am I missing something?

what does the "dot" do to the "vertical" bits? :wink:

(and you'll need an H1 and an H2)
 
For each half of the rectangles vertical sides the magnetic field moves in equal an opposite directions and therefore would cancel each other out? So it is just..

[itex]I_{1enc} = H_1 \cdot y = 20\cdot 0.05 = 1A[/itex]
[itex]I_{2enc} = H_2 \cdot y = 30\cdot 0.05 = 1.5A[/itex]

Seem correct?
 
hi zhillyz! :smile:
zhillyz said:
For each half of the rectangles vertical sides the magnetic field moves in equal an opposite directions and therefore would cancel each other out? So it is just..

no, you're missing the point (or the dot) …

H.dl is 0 because H is perpendicular to that part of the circuit! :rolleyes:

otherwise correct :smile:
 
Thank you very kindly :).
 

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