What is the current in each resistor in a complex RC circuit?

Click For Summary
SUMMARY

The discussion focuses on calculating the current in a complex RC circuit, specifically determining the currents I1, I2, and I3 through various resistors. The user initially applies Ohm's Law (V=IR) to find I1, resulting in a current of approximately 7.92 A. The user then sets up two loop equations based on Kirchhoff's loop and junction rules to solve for I2 and I3, indicating a structured approach to circuit analysis.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Familiarity with Kirchhoff's Loop Rule
  • Knowledge of Kirchhoff's Junction Rule
  • Basic concepts of RC circuits
NEXT STEPS
  • Study Kirchhoff's Laws in detail for circuit analysis
  • Learn about series and parallel resistor combinations
  • Explore the time constant in RC circuits and its implications
  • Practice solving complex circuit problems using simulation tools like LTspice
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone looking to deepen their understanding of RC circuit analysis and current calculations.

kevbot010
Messages
2
Reaction score
0

Homework Statement



Find the current I1 in the 1.2
resistor
at the bottom of the circuit between the two
power supplies.
Answer in units of A.
015 (part 2 of 3) 10.0 points
Determine I2.
Answer in units of A.
016 (part 3 of 3) 10.0 points
Determine I3.
Answer in units of A.

Homework Equations


I=Ifinal(e^-t/RC)
V=IR



The Attempt at a Solution



V=IR
I=V/R
I=9.5/1.2
I=7.91667A

The attachment is a picture of the circuit. I really have no idea how to solve this and could use some helpful explanation. Thanks!

Kevin
 

Attachments

  • RC Circuit.png
    RC Circuit.png
    6.7 KB · Views: 454
Last edited:
Physics news on Phys.org
ok i understand i must use the loop rule and the junction rule.

I made it where there are two loops
Loop1:
9.5-1.2I1+2-3-5.4I2-3.1=0

Loop2:
3.1-5.4I2-8.4I3=0

I think this may be right, if it is i am still unsure of how to continue with the problem
 

Similar threads

Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
8K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 41 ·
2
Replies
41
Views
7K
Replies
1
Views
3K