What is the determinant of a Lorentz transformation matrix?

Click For Summary
The determinant of a Lorentz transformation matrix is either +1 or -1, reflecting the preservation of spacetime intervals. Any Lorentz transformation can be classified as a boost, a rotation, or a combination of both, with 3D rotations having a determinant of ±1. The product of two Lorentz transformation matrices also maintains this property, as shown by the equation det(LR) = det(L)det(R). Reversal of the time or space axis results in a determinant of -1, confirming that all Lorentz transformations yield determinants of ±1. The relationship η = ATηA, where A is a Lorentz transformation matrix, further illustrates the invariance of the metric under such transformations.
vin300
Messages
602
Reaction score
4
I have been asked to prove that the determinant of any matrix representing a Lorentz transformation is plus or minus 1. I can see that the determinant of the Lorentz transformation matrix is 1, but don't know how to prove +-1 in general. How to generalise the lorentz transformation? I've also read that rotations in the spatial planes also constitute L.T., that any transformation that keeps the metric invariant is an L.T.
 
Physics news on Phys.org
Since any arbitrary LT is either a boost between timelike and spacelike directions, a rotation between spacelike directions, or a combination of the two, I think all you need is to check that the determinant of a 3D rotation is \pm 1. After that, if \underline L \underline R both represent LT's, then what do you know about

\det (\underline L \underline R) = ?
 
Reversal of the space or time axis produces a matrix of determinant -1. That proves that any LT matrix has determinant \pm 1. det(LR)=det(L)det(R), so again, the resulting matrix has determinant \pm 1.
 
Last edited:
How to prove that the matrix version of ηa'b'= Ama'Anb'ηmn is η= ATηA, where A is an LT matrix?
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 101 ·
4
Replies
101
Views
7K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 89 ·
3
Replies
89
Views
15K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K