What is the difference between energy and relativistic mass?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
32 replies · 6K views
Meir Achuz said:
In the modern interpretation, m is the "invariant mass" of an object, and the equation E=mc^2 holds only in the rest system.



is the rest system to viewer?
 
Physics news on Phys.org
dreamfly said:
is the rest system to viewer?

I'm pretty sure Meir meant "the rest system of the object in question."

In the usual modern terminology the energy of an object is

[tex]E = \frac {mc^2}{\sqrt {1 - u^2 / c^2}}[/tex]

where [itex]u[/itex] is the speed of the object in whatever reference frame you're working in, and [itex]m[/itex] is the invariant mass, which is often called the "rest mass". This reduces to [itex]E = mc^2[/itex] when [itex]u = 0[/itex], i.e. when the object is at rest.
 
jtbell said:
I'm pretty sure Meir meant "the rest system of the object in question."

In the usual modern terminology the energy of an object is

[tex]E = \frac {mc^2}{\sqrt {1 - u^2 / c^2}}[/tex]

where [itex]u[/itex] is the speed of the object in whatever reference frame you're working in, and [itex]m[/itex] is the invariant mass, which is often called the "rest mass". This reduces to [itex]E = mc^2[/itex] when [itex]u = 0[/itex], i.e. when the object is at rest.



Thank you!