What Is the Displacement of the Wandering Wolf?

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SUMMARY

The displacement of the wandering wolf, after traveling 64 m [N15E], 93 m [N20W], and 167 m [N], is calculated to be 324 m [N5W]. The calculation utilizes the formula Δd = d3 - d2 - d1, where d3 represents the final position, and d1 and d2 represent the previous movements. The sign convention applied considers north to southeast as positive and south to northwest as negative. Visualizing the wolf's path on paper aids in understanding the displacement as the shortest distance between the initial and final positions.

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Homework Statement


A wolf wanders 64 m [N15E], 93m[N20W], and 167 m [N]. What is her displacement?

North to South east is considered positive by my sign convention, and from south to north west, it is considered to be negative, once again by my sign convention. I've never seen problems like this before, I did make an attempt but i am getting the answer wrong.


Homework Equations



Δ d = d3 - d2 - d1



The Attempt at a Solution



Δd= (+ 167m [N]) - ( -93 m [N20W]) - (+ 64m [N15E])
= 324 m [N5W]
 
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Displacement is the shortest distance between your initial distance and final distance. Try drawing the wolfs movement on a paper with the angles then draw a line between the initial distance and final distance that is the displacement
 
So then what point is my point of reference, and i tried it but still nothing. Can someone do it and show how they got the right answer??
 

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