What is the distance between station a and station b?

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SUMMARY

The distance between station A and station B can be calculated using kinematic equations. A train accelerates uniformly at 0.5 m/s² for 50 seconds, reaching a final speed of 25 m/s. It then travels at this speed for 120 seconds before decelerating at -2.5 m/s² until it comes to a stop at station B. The total distance covered is 3.75 x 10³ meters, which is the sum of the distances during acceleration, constant speed, and deceleration phases.

PREREQUISITES
  • Kinematic equations for uniformly accelerated motion
  • Understanding of velocity-time graphs
  • Basic principles of acceleration and deceleration
  • Ability to calculate area under a graph for displacement
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  • Learn how to construct and interpret velocity-time graphs
  • Practice problems involving uniform acceleration and deceleration
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Students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples of motion analysis in train systems.

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Homework Statement



a train starts from station a with a uniform acceleration of 5.00 x 10^-1 m/s^2 (east) and attains full speed after 50.0s. It travels at full speed for 1.20 x 10^2 s, then is brought to rest at station b by the application of the brakes which produces a constant acceleration of -2.50 m/s^2 (east). find the distance between station a and station b

The Attempt at a Solution


i tried adding station a and b's displacements but it didn't add up to 3.75x10^3 m (the answer)

i got station a's displacement by finding vfinal then using d=vft-1/2at^2 and added that to the other displacement and yea didn't work.
 
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Draw the v-t graph - the displacement is the area under the graph.
Note: considering the stations are not moving, both their displacement's are 0.
Station a will be at position x=0m.

In the first stage of the journey, you need to find the final speed.
In the last stage you need to find the time to decelerate to rest.
 

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